Y=2v^2+12v+18

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Solution for Y=2v^2+12v+18 equation: 



=2Y^2+12Y+18

We move all terms to the left:

-(2Y^2+12Y+18)=0

We get rid of parentheses

-2Y^2-12Y-18=0

a = -2; b = -12; c = -18;
Δ = b2-4ac
Δ = -122-4·(-2)·(-18)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{12}{-4}=-3$

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